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3/x=9/(x+2)
We move all terms to the left:
3/x-(9/(x+2))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
3x/3x^2+(-(9*x)/3x^2=0
We add all the numbers together, and all the variables
3x/3x^2+(-(+9x)/3x^2=0
We multiply all the terms by the denominator
3x+(-(+9x)=0
We calculate terms in parentheses: +(-(+9x), so:
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| 5/3x2+8=2/3x2+57 | | 3/4x-24=30 | | x2+3=84 | | 11y-16-15=2•45 | | (3x/2)+4=(5x/2)+2 | | 6x2-54x=0 | | 5(x+3)=4×19 | | 3x+6=6x−3 | | 12=-16t^2+136t | | 3x=10+2¥ | | (2x+7)2=(2x+1) | | 4n-3=2n+9= | | 13=m-2-5 | | 8x+3x=1 | | (Y+5)(y+2)=(y+1)(y-3) | | 5=14÷x-2 | | 66=8u−14 | | 8n-16=12n-28 | | 4(x-2)=2(6-3x) | | 72−x=20·3 | | 75x=55 | | 7a=12a-6 | | 7/(x+3)=3/(x-1) | | -(2/3a-1/3)+1/3a=-4 | | 8+8x=9x+4 | | 0.7x-10=-12 | | a-14=3 | | -3(-3x+12)-4x=10-6 | | −18x+9=72 | | 44+2x=10x-4 | | 2x+2x+8=4012x=40x=40/12 | | 3x+12+2x+10=4 |