3/x=9/3x+20

Solution for 3/x=9/3x+20 equation:

3/x=9/3x+20

We move all terms to the left:

3/x-(9/3x+20)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x+20)!=0

x∈R


We get rid of parentheses

3/x-9/3x-20=0

We calculate fractions


9x/3x^2+(-9x)/3x^2-20=0

We multiply all the terms by the denominator


9x+(-9x)-20*3x^2=0

Wy multiply elements

-60x^2+9x+(-9x)=0

We get rid of parentheses

-60x^2+9x-9x=0

We add all the numbers together, and all the variables

-60x^2=0

a = -60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-60)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-120}=0$