3/y+4/2-y=7/y

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Solution for 3/y+4/2-y=7/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-y+4/2 = 7/y // - 7/y

3/y-y-(7/y)+4/2 = 0

3/y-y-7*y^-1+4/2 = 0

2*y^0-1*y^1-4*y^-1 = 0

(2*y^1-1*y^2-4*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^1-1*y^2-4*y^0) = 0

y^1

2*y-y^2-4 = 0

2*y-y^2-4 = 0

DELTA = 2^2-(-4*(-1)*4)

DELTA = -12

DELTA < 0

y in { } 

y belongs to the empty set

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