3/y-1/12=7/4y

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Solution for 3/y-1/12=7/4y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-(1/12) = (7/4)*y // - (7/4)*y

3/y-((7/4)*y)-(1/12) = 0

(-7/4)*y+3/y-1/12 = 0

3*y^-1-7/4*y^1-1/12*y^0 = 0

(3*y^0-7/4*y^2-1/12*y^1)/(y^1) = 0 // * y^2

y^1*(3*y^0-7/4*y^2-1/12*y^1) = 0

y^1

(-7/4)*y^2+(-1/12)*y+3 = 0

(-7/4)*y^2+(-1/12)*y+3 = 0

DELTA = (-1/12)^2-(3*4*(-7/4))

DELTA = 3025/144

DELTA > 0

y = ((3025/144)^(1/2)-(-1/12))/(2*(-7/4)) or y = (-(-1/12)-(3025/144)^(1/2))/(2*(-7/4))

y = -4/3 or y = 9/7

y in { -4/3, 9/7} 

y in { -4/3, 9/7 }

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