3/y-1=y/2

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Solution for 3/y-1=y/2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-1 = y/2 // - y/2

3/y-(y/2)-1 = 0

3*y^-1-1/2*y^1-1*y^0 = 0

(3*y^0-1/2*y^2-1*y^1)/(y^1) = 0 // * y^2

y^1*(3*y^0-1/2*y^2-1*y^1) = 0

y^1

(-1/2)*y^2-y+3 = 0

(-1/2)*y^2-y+3 = 0

DELTA = (-1)^2-(3*4*(-1/2))

DELTA = 7

DELTA > 0

y = (7^(1/2)+1)/(2*(-1/2)) or y = (1-7^(1/2))/(2*(-1/2))

y = -(7^(1/2)+1) or y = 7^(1/2)-1

y in { -(7^(1/2)+1), 7^(1/2)-1} 

y in { -(7^(1/2)+1), 7^(1/2)-1 }

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