3/y-9=13+1/8y

Solution for 3/y-9=13+1/8y equation:

D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-9 = (1/8)*y+13 // - (1/8)*y+13

3/y-((1/8)*y)-13-9 = 0

(-1/8)*y+3/y-13-9 = 0

3*y^-1-1/8*y^1-22*y^0 = 0

(3*y^0-1/8*y^2-22*y^1)/(y^1) = 0 // * y^2

y^1*(3*y^0-1/8*y^2-22*y^1) = 0

y^1

(-1/8)*y^2-22*y+3 = 0

(-1/8)*y^2-22*y+3 = 0

DELTA = (-22)^2-(3*4*(-1/8))

DELTA = 971/2

DELTA > 0

y = ((971/2)^(1/2)+22)/(2*(-1/8)) or y = (22-(971/2)^(1/2))/(2*(-1/8))

y = -4*((971/2)^(1/2)+22) or y = -4*(22-(971/2)^(1/2))

y in { -4*((971/2)^(1/2)+22), -4*(22-(971/2)^(1/2))} 

y in { -4*((971/2)^(1/2)+22), -4*(22-(971/2)^(1/2)) }