30+(10x-10)+(180+(12x-4))=180

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Solution for 30+(10x-10)+(180+(12x-4))=180 equation: 



30+(10x-10)+(180+(12x-4))=180

We move all terms to the left:

30+(10x-10)+(180+(12x-4))-(180)=0

We add all the numbers together, and all the variables

(10x-10)+(180+(12x-4))-150=0

We get rid of parentheses

10x+(180+(12x-4))-10-150=0



We calculate terms in parentheses: +(180+(12x-4)), so:

180+(12x-4)

determiningTheFunctionDomain
(12x-4)+180

We get rid of parentheses

12x-4+180

We add all the numbers together, and all the variables

12x+176

Back to the equation:

+(12x+176)



We add all the numbers together, and all the variables

10x+(12x+176)-160=0

We get rid of parentheses

10x+12x+176-160=0

We add all the numbers together, and all the variables

22x+16=0

We move all terms containing x to the left, all other terms to the right

22x=-16

x=-16/22

x=-8/11

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