30+(2c-43)+(3c+8)=180

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Solution for 30+(2c-43)+(3c+8)=180 equation: 



30+(2c-43)+(3c+8)=180

We move all terms to the left:

30+(2c-43)+(3c+8)-(180)=0

We add all the numbers together, and all the variables

(2c-43)+(3c+8)-150=0

We get rid of parentheses

2c+3c-43+8-150=0

We add all the numbers together, and all the variables

5c-185=0

We move all terms containing c to the left, all other terms to the right

5c=185

c=185/5

c=37

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