30+3x=7(1+x)-5

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Solution for 30+3x=7(1+x)-5 equation: 



30+3x=7(1+x)-5

We move all terms to the left:

30+3x-(7(1+x)-5)=0

We add all the numbers together, and all the variables

3x-(7(x+1)-5)+30=0



We calculate terms in parentheses: -(7(x+1)-5), so:

7(x+1)-5

We multiply parentheses

7x+7-5

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We get rid of parentheses

3x-7x-2+30=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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