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30+8b=2+(5b-8)
We move all terms to the left:
30+8b-(2+(5b-8))=0
We calculate terms in parentheses: -(2+(5b-8)), so:We get rid of parentheses
2+(5b-8)
determiningTheFunctionDomain (5b-8)+2
We get rid of parentheses
5b-8+2
We add all the numbers together, and all the variables
5b-6
Back to the equation:
-(5b-6)
8b-5b+6+30=0
We add all the numbers together, and all the variables
3b+36=0
We move all terms containing b to the left, all other terms to the right
3b=-36
b=-36/3
b=-12
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