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30+x=3/2x
We move all terms to the left:
30+x-(3/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+3/2x)+30=0
We get rid of parentheses
x-3/2x+30=0
We multiply all the terms by the denominator
x*2x+30*2x-3=0
Wy multiply elements
2x^2+60x-3=0
a = 2; b = 60; c = -3;
Δ = b2-4ac
Δ = 602-4·2·(-3)
Δ = 3624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3624}=\sqrt{4*906}=\sqrt{4}*\sqrt{906}=2\sqrt{906}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{906}}{2*2}=\frac{-60-2\sqrt{906}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{906}}{2*2}=\frac{-60+2\sqrt{906}}{4} $
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