30-(2c+4)=2(c-3)+c

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Solution for 30-(2c+4)=2(c-3)+c equation: 



30-(2c+4)=2(c-3)+c

We move all terms to the left:

30-(2c+4)-(2(c-3)+c)=0

We get rid of parentheses

-2c-(2(c-3)+c)-4+30=0



We calculate terms in parentheses: -(2(c-3)+c), so:

2(c-3)+c

We add all the numbers together, and all the variables

c+2(c-3)

We multiply parentheses

c+2c-6

We add all the numbers together, and all the variables

3c-6

Back to the equation:

-(3c-6)



We add all the numbers together, and all the variables

-2c-(3c-6)+26=0

We get rid of parentheses

-2c-3c+6+26=0

We add all the numbers together, and all the variables

-5c+32=0

We move all terms containing c to the left, all other terms to the right

-5c=-32

c=-32/-5

c=6+2/5

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