30-6(3z+1)=3(2z-4)

Solution for 30-6(3z+1)=3(2z-4) equation:

30-6(3z+1)=3(2z-4)

We move all terms to the left:

30-6(3z+1)-(3(2z-4))=0

We multiply parentheses

-18z-(3(2z-4))-6+30=0


We calculate terms in parentheses: -(3(2z-4)), so:

3(2z-4)

We multiply parentheses

6z-12

Back to the equation:

-(6z-12)


We add all the numbers together, and all the variables

-18z-(6z-12)+24=0

We get rid of parentheses

-18z-6z+12+24=0

We add all the numbers together, and all the variables

-24z+36=0

We move all terms containing z to the left, all other terms to the right

-24z=-36

z=-36/-24

z=1+1/2