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30/2x=10/x+2
We move all terms to the left:
30/2x-(10/x+2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
30/2x-10/x-2=0
We calculate fractions
30x/2x^2+(-20x)/2x^2-2=0
We multiply all the terms by the denominator
30x+(-20x)-2*2x^2=0
Wy multiply elements
-4x^2+30x+(-20x)=0
We get rid of parentheses
-4x^2+30x-20x=0
We add all the numbers together, and all the variables
-4x^2+10x=0
a = -4; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-4)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-4}=\frac{-20}{-8} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-4}=\frac{0}{-8} =0 $
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