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300+2/3x=1x
We move all terms to the left:
300+2/3x-(1x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+2/3x+300=0
We multiply all the terms by the denominator
-1x*3x+300*3x+2=0
Wy multiply elements
-3x^2+900x+2=0
a = -3; b = 900; c = +2;
Δ = b2-4ac
Δ = 9002-4·(-3)·2
Δ = 810024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{810024}=\sqrt{4*202506}=\sqrt{4}*\sqrt{202506}=2\sqrt{202506}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(900)-2\sqrt{202506}}{2*-3}=\frac{-900-2\sqrt{202506}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(900)+2\sqrt{202506}}{2*-3}=\frac{-900+2\sqrt{202506}}{-6} $
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