3000x+3000-3000x-100x2+100=0

Solution for 3000x+3000-3000x-100x2+100=0 equation:

3000x+3000-3000x-100x^2+100=0

We add all the numbers together, and all the variables

-100x^2+3100=0

a = -100; b = 0; c = +3100;
Δ = b2-4ac
Δ = 02-4·(-100)·3100
Δ = 1240000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1240000}=\sqrt{40000*31}=\sqrt{40000}*\sqrt{31}=200\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{31}}{2*-100}=\frac{0-200\sqrt{31}}{-200}
=-\frac{200\sqrt{31}}{-200}
=-\frac{\sqrt{31}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{31}}{2*-100}=\frac{0+200\sqrt{31}}{-200}
=\frac{200\sqrt{31}}{-200}
=\frac{\sqrt{31}}{-1}
$