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301.44=3.14r(r+10)
We move all terms to the left:
301.44-(3.14r(r+10))=0
We calculate terms in parentheses: -(3.14r(r+10)), so:We get rid of parentheses
3.14r(r+10)
We multiply parentheses
3r^2+30r
Back to the equation:
-(3r^2+30r)
-3r^2-30r+301.44=0
a = -3; b = -30; c = +301.44;
Δ = b2-4ac
Δ = -302-4·(-3)·301.44
Δ = 4517.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{4517.28}}{2*-3}=\frac{30-\sqrt{4517.28}}{-6} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{4517.28}}{2*-3}=\frac{30+\sqrt{4517.28}}{-6} $
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