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3025=c2
We move all terms to the left:
3025-(c2)=0
We add all the numbers together, and all the variables
-1c^2+3025=0
a = -1; b = 0; c = +3025;
Δ = b2-4ac
Δ = 02-4·(-1)·3025
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*-1}=\frac{-110}{-2} =+55 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*-1}=\frac{110}{-2} =-55 $
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