30=(t/5)-10

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Solution for 30=(t/5)-10 equation: 



30=(t/5)-10

We move all terms to the left:

30-((t/5)-10)=0

We add all the numbers together, and all the variables

-((+t/5)-10)+30=0

We multiply all the terms by the denominator


-((+t+30*5)-10)=0



We calculate terms in parentheses: -((+t+30*5)-10), so:

(+t+30*5)-10

We add all the numbers together, and all the variables

(t+150)-10

We get rid of parentheses

t+150-10

We add all the numbers together, and all the variables

t+140

Back to the equation:

-(t+140)



We get rid of parentheses

-t-140=0

We add all the numbers together, and all the variables

-1t-140=0

We move all terms containing t to the left, all other terms to the right

-t=140

t=140/-1

t=-140

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