30=-2(c+-2)+-40

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Solution for 30=-2(c+-2)+-40 equation: 



30=-2(c+-2)+-40

We move all terms to the left:

30-(-2(c+-2)+-40)=0

We add all the numbers together, and all the variables

-(-2(c-2)+-40)+30=0

We use the square of the difference formula

-(-2(c-2)-40)+30=0



We calculate terms in parentheses: -(-2(c-2)-40), so:

-2(c-2)-40

We multiply parentheses

-2c+4-40

We add all the numbers together, and all the variables

-2c-36

Back to the equation:

-(-2c-36)



We get rid of parentheses

2c+36+30=0

We add all the numbers together, and all the variables

2c+66=0

We move all terms containing c to the left, all other terms to the right

2c=-66

c=-66/2

c=-33

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