30=10(5-y)+4y

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Solution for 30=10(5-y)+4y equation: 



30=10(5-y)+4y

We move all terms to the left:

30-(10(5-y)+4y)=0

We add all the numbers together, and all the variables

-(10(-1y+5)+4y)+30=0



We calculate terms in parentheses: -(10(-1y+5)+4y), so:

10(-1y+5)+4y

We add all the numbers together, and all the variables

4y+10(-1y+5)

We multiply parentheses

4y-10y+50

We add all the numbers together, and all the variables

-6y+50

Back to the equation:

-(-6y+50)



We get rid of parentheses

6y-50+30=0

We add all the numbers together, and all the variables

6y-20=0

We move all terms containing y to the left, all other terms to the right

6y=20

y=20/6

y=3+1/3

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