30=10+10(c+11)

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Solution for 30=10+10(c+11) equation: 



30=10+10(c+11)

We move all terms to the left:

30-(10+10(c+11))=0



We calculate terms in parentheses: -(10+10(c+11)), so:

10+10(c+11)

determiningTheFunctionDomain
10(c+11)+10

We multiply parentheses

10c+110+10

We add all the numbers together, and all the variables

10c+120

Back to the equation:

-(10c+120)



We get rid of parentheses

-10c-120+30=0

We add all the numbers together, and all the variables

-10c-90=0

We move all terms containing c to the left, all other terms to the right

-10c=90

c=90/-10

c=-9

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