30=2(3c+3)

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Solution for 30=2(3c+3) equation: 



30=2(3c+3)

We move all terms to the left:

30-(2(3c+3))=0



We calculate terms in parentheses: -(2(3c+3)), so:

2(3c+3)

We multiply parentheses

6c+6

Back to the equation:

-(6c+6)



We get rid of parentheses

-6c-6+30=0

We add all the numbers together, and all the variables

-6c+24=0

We move all terms containing c to the left, all other terms to the right

-6c=-24

c=-24/-6

c=+4

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