30=2(y-5)-7y

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Solution for 30=2(y-5)-7y equation: 



30=2(y-5)-7y

We move all terms to the left:

30-(2(y-5)-7y)=0



We calculate terms in parentheses: -(2(y-5)-7y), so:

2(y-5)-7y

We add all the numbers together, and all the variables

-7y+2(y-5)

We multiply parentheses

-7y+2y-10

We add all the numbers together, and all the variables

-5y-10

Back to the equation:

-(-5y-10)



We get rid of parentheses

5y+10+30=0

We add all the numbers together, and all the variables

5y+40=0

We move all terms containing y to the left, all other terms to the right

5y=-40

y=-40/5

y=-8

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