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30=2x^2+7x
We move all terms to the left:
30-(2x^2+7x)=0
We get rid of parentheses
-2x^2-7x+30=0
a = -2; b = -7; c = +30;
Δ = b2-4ac
Δ = -72-4·(-2)·30
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*-2}=\frac{-10}{-4} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*-2}=\frac{24}{-4} =-6 $
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