30=3(b+5)

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Solution for 30=3(b+5) equation: 



30=3(b+5)

We move all terms to the left:

30-(3(b+5))=0



We calculate terms in parentheses: -(3(b+5)), so:

3(b+5)

We multiply parentheses

3b+15

Back to the equation:

-(3b+15)



We get rid of parentheses

-3b-15+30=0

We add all the numbers together, and all the variables

-3b+15=0

We move all terms containing b to the left, all other terms to the right

-3b=-15

b=-15/-3

b=+5

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