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30m=125+5(m+5)
We move all terms to the left:
30m-(125+5(m+5))=0
We calculate terms in parentheses: -(125+5(m+5)), so:We get rid of parentheses
125+5(m+5)
determiningTheFunctionDomain 5(m+5)+125
We multiply parentheses
5m+25+125
We add all the numbers together, and all the variables
5m+150
Back to the equation:
-(5m+150)
30m-5m-150=0
We add all the numbers together, and all the variables
25m-150=0
We move all terms containing m to the left, all other terms to the right
25m=150
m=150/25
m=6
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