30q2+38q-16=0

Solution for 30q2+38q-16=0 equation:

30q^2+38q-16=0

a = 30; b = 38; c = -16;
Δ = b2-4ac
Δ = 382-4·30·(-16)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-58}{2*30}=\frac{-96}{60}
=-1+3/5
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+58}{2*30}=\frac{20}{60}
=1/3
$