30t+-5t2=9

Solution for 30t+-5t2=9 equation:

30t+-5t^2=9

We move all terms to the left:

30t+-5t^2-(9)=0

determiningTheFunctionDomain
-5t^2+30t-9+=0

We add all the numbers together, and all the variables

-5t^2+30t=0

a = -5; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-5)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-5}=\frac{-60}{-10}
=+6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-5}=\frac{0}{-10}
=0
$