30t+40(3-t)=100

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Solution for 30t+40(3-t)=100 equation: 



30t+40(3-t)=100

We move all terms to the left:

30t+40(3-t)-(100)=0

We add all the numbers together, and all the variables

30t+40(-1t+3)-100=0

We multiply parentheses

30t-40t+120-100=0

We add all the numbers together, and all the variables

-10t+20=0

We move all terms containing t to the left, all other terms to the right

-10t=-20

t=-20/-10

t=+2

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