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30v^2+19v-63=0
a = 30; b = 19; c = -63;
Δ = b2-4ac
Δ = 192-4·30·(-63)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7921}=89$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-89}{2*30}=\frac{-108}{60} =-1+4/5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+89}{2*30}=\frac{70}{60} =1+1/6 $
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