30x+(10/3)x=3300

Solution for 30x+(10/3)x=3300 equation:

30x+(10/3)x=3300

We move all terms to the left:

30x+(10/3)x-(3300)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

30x+(+10/3)x-3300=0

We multiply parentheses

10x^2+30x-3300=0

a = 10; b = 30; c = -3300;
Δ = b2-4ac
Δ = 302-4·10·(-3300)
Δ = 132900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132900}=\sqrt{100*1329}=\sqrt{100}*\sqrt{1329}=10\sqrt{1329}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{1329}}{2*10}=\frac{-30-10\sqrt{1329}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{1329}}{2*10}=\frac{-30+10\sqrt{1329}}{20}
$