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30x^2+1=11x
We move all terms to the left:
30x^2+1-(11x)=0
a = 30; b = -11; c = +1;
Δ = b2-4ac
Δ = -112-4·30·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*30}=\frac{10}{60} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*30}=\frac{12}{60} =1/5 $
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