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30x^2-5x=5
We move all terms to the left:
30x^2-5x-(5)=0
a = 30; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·30·(-5)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*30}=\frac{-20}{60} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*30}=\frac{30}{60} =1/2 $
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