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30x^2=50
We move all terms to the left:
30x^2-(50)=0
a = 30; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·30·(-50)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*30}=\frac{0-20\sqrt{15}}{60} =-\frac{20\sqrt{15}}{60} =-\frac{\sqrt{15}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*30}=\frac{0+20\sqrt{15}}{60} =\frac{20\sqrt{15}}{60} =\frac{\sqrt{15}}{3} $
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