30y+(-(3y+2)-(y+3))=16y-(3y-(6-9y))

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Solution for 30y+(-(3y+2)-(y+3))=16y-(3y-(6-9y)) equation: 



30y+-(3y+2)-(y+3)=16y-3y-(6-9y)

We move all terms to the left:

30y+-(3y+2)-(y+3)-(16y-3y-(6-9y))=0

We add all the numbers together, and all the variables

30y-(3y+2)-(y+3)-(16y-3y-(-9y+6))+=0

We add all the numbers together, and all the variables

30y-(3y+2)-(y+3)-(16y-3y-(-9y+6))=0

We get rid of parentheses

30y-3y-y-(16y-3y-(-9y+6))-2-3=0



We calculate terms in parentheses: -(16y-3y-(-9y+6)), so:

16y-3y-(-9y+6)

We add all the numbers together, and all the variables

13y-(-9y+6)

We get rid of parentheses

13y+9y-6

We add all the numbers together, and all the variables

22y-6

Back to the equation:

-(22y-6)



We add all the numbers together, and all the variables

26y-(22y-6)-5=0

We get rid of parentheses

26y-22y+6-5=0

We add all the numbers together, and all the variables

4y+1=0

We move all terms containing y to the left, all other terms to the right

4y=-1

y=-1/4

y=-1/4

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