30y-35=5(6y-7)

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Solution for 30y-35=5(6y-7) equation: 



30y-35=5(6y-7)

We move all terms to the left:

30y-35-(5(6y-7))=0



We calculate terms in parentheses: -(5(6y-7)), so:

5(6y-7)

We multiply parentheses

30y-35

Back to the equation:

-(30y-35)



We get rid of parentheses

30y-30y+35-35=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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