30y2+29y-7=0

Solution for 30y2+29y-7=0 equation:

30y^2+29y-7=0

a = 30; b = 29; c = -7;
Δ = b2-4ac
Δ = 292-4·30·(-7)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-41}{2*30}=\frac{-70}{60}
=-1+1/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+41}{2*30}=\frac{12}{60}
=1/5
$