31+3(4x+3)=4(6x+1)

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Solution for 31+3(4x+3)=4(6x+1) equation:



31+3(4x+3)=4(6x+1)
We move all terms to the left:
31+3(4x+3)-(4(6x+1))=0
We multiply parentheses
12x-(4(6x+1))+9+31=0
We calculate terms in parentheses: -(4(6x+1)), so:
4(6x+1)
We multiply parentheses
24x+4
Back to the equation:
-(24x+4)
We add all the numbers together, and all the variables
12x-(24x+4)+40=0
We get rid of parentheses
12x-24x-4+40=0
We add all the numbers together, and all the variables
-12x+36=0
We move all terms containing x to the left, all other terms to the right
-12x=-36
x=-36/-12
x=+3

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