31+4r=3(2r+7)

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Solution for 31+4r=3(2r+7) equation: 



31+4r=3(2r+7)

We move all terms to the left:

31+4r-(3(2r+7))=0



We calculate terms in parentheses: -(3(2r+7)), so:

3(2r+7)

We multiply parentheses

6r+21

Back to the equation:

-(6r+21)



We get rid of parentheses

4r-6r-21+31=0

We add all the numbers together, and all the variables

-2r+10=0

We move all terms containing r to the left, all other terms to the right

-2r=-10

r=-10/-2

r=+5

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