31+5b=1+2(7b-3)

Solution for 31+5b=1+2(7b-3) equation:

31+5b=1+2(7b-3)

We move all terms to the left:

31+5b-(1+2(7b-3))=0


We calculate terms in parentheses: -(1+2(7b-3)), so:

1+2(7b-3)

determiningTheFunctionDomain
2(7b-3)+1

We multiply parentheses

14b-6+1

We add all the numbers together, and all the variables

14b-5

Back to the equation:

-(14b-5)


We get rid of parentheses

5b-14b+5+31=0

We add all the numbers together, and all the variables

-9b+36=0

We move all terms containing b to the left, all other terms to the right

-9b=-36

b=-36/-9

b=+4