31-(-2c+4)=2(c+6)+c

Solution for 31-(-2c+4)=2(c+6)+c equation:

31-(-2c+4)=2(c+6)+c

We move all terms to the left:

31-(-2c+4)-(2(c+6)+c)=0

We get rid of parentheses

2c-(2(c+6)+c)-4+31=0


We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)


We add all the numbers together, and all the variables

2c-(3c+12)+27=0

We get rid of parentheses

2c-3c-12+27=0

We add all the numbers together, and all the variables

-1c+15=0

We move all terms containing c to the left, all other terms to the right

-c=-15

c=-15/-1

c=+15