31-(2c+3)=+2(c+4)+c

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Solution for 31-(2c+3)=+2(c+4)+c equation:



31-(2c+3)=+2(c+4)+c
We move all terms to the left:
31-(2c+3)-(+2(c+4)+c)=0
We get rid of parentheses
-2c-(+2(c+4)+c)-3+31=0
We calculate terms in parentheses: -(+2(c+4)+c), so:
+2(c+4)+c
determiningTheFunctionDomain 2(c+4)+c
We add all the numbers together, and all the variables
c+2(c+4)
We multiply parentheses
c+2c+8
We add all the numbers together, and all the variables
3c+8
Back to the equation:
-(3c+8)
We add all the numbers together, and all the variables
-2c-(3c+8)+28=0
We get rid of parentheses
-2c-3c-8+28=0
We add all the numbers together, and all the variables
-5c+20=0
We move all terms containing c to the left, all other terms to the right
-5c=-20
c=-20/-5
c=+4

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