31-(2c+3)=+2(c+4)+c

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Solution for 31-(2c+3)=+2(c+4)+c equation: 



31-(2c+3)=+2(c+4)+c

We move all terms to the left:

31-(2c+3)-(+2(c+4)+c)=0

We get rid of parentheses

-2c-(+2(c+4)+c)-3+31=0



We calculate terms in parentheses: -(+2(c+4)+c), so:

+2(c+4)+c

determiningTheFunctionDomain
2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We add all the numbers together, and all the variables

-2c-(3c+8)+28=0

We get rid of parentheses

-2c-3c-8+28=0

We add all the numbers together, and all the variables

-5c+20=0

We move all terms containing c to the left, all other terms to the right

-5c=-20

c=-20/-5

c=+4

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