31-4a=-5-5(1+5a)

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Solution for 31-4a=-5-5(1+5a) equation: 



31-4a=-5-5(1+5a)

We move all terms to the left:

31-4a-(-5-5(1+5a))=0

We add all the numbers together, and all the variables

-4a-(-5-5(5a+1))+31=0



We calculate terms in parentheses: -(-5-5(5a+1)), so:

-5-5(5a+1)

determiningTheFunctionDomain
-5(5a+1)-5

We multiply parentheses

-25a-5-5

We add all the numbers together, and all the variables

-25a-10

Back to the equation:

-(-25a-10)



We get rid of parentheses

-4a+25a+10+31=0

We add all the numbers together, and all the variables

21a+41=0

We move all terms containing a to the left, all other terms to the right

21a=-41

a=-41/21

a=-1+20/21

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