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31/2x-51/3x.x=2/5
We move all terms to the left:
31/2x-51/3x.x-(2/5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x.x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
31/2x-51/3x.x-(+2/5)=0
We get rid of parentheses
31/2x-51/3x.x-2/5=0
We calculate fractions
(-36x^2)/30x^2+465x/30x^2+(-2550x)/30x^2=0
We multiply all the terms by the denominator
(-36x^2)+465x+(-2550x)=0
We get rid of parentheses
-36x^2+465x-2550x=0
We add all the numbers together, and all the variables
-36x^2-2085x=0
a = -36; b = -2085; c = 0;
Δ = b2-4ac
Δ = -20852-4·(-36)·0
Δ = 4347225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4347225}=2085$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2085)-2085}{2*-36}=\frac{0}{-72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2085)+2085}{2*-36}=\frac{4170}{-72} =-57+11/12 $
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