31/3(1+2x)=51/2(2x-1)

Solution for 31/3(1+2x)=51/2(2x-1) equation:

31/3(1+2x)=51/2(2x-1)

We move all terms to the left:

31/3(1+2x)-(51/2(2x-1))=0


Domain of the equation: 3(1+2x)!=0

x∈R



Domain of the equation: 2(2x-1))!=0

x∈R


We add all the numbers together, and all the variables

31/3(2x+1)-(51/2(2x-1))=0

We calculate fractions


(62x2/(3(2x+1)*2(2x-1)))+(-153x2/(3(2x+1)*2(2x-1)))=0


We calculate terms in parentheses: +(62x2/(3(2x+1)*2(2x-1))), so:

62x2/(3(2x+1)*2(2x-1))

We multiply all the terms by the denominator


62x2

We add all the numbers together, and all the variables

62x^2

Back to the equation:

+(62x^2)



We calculate terms in parentheses: +(-153x2/(3(2x+1)*2(2x-1))), so:

-153x2/(3(2x+1)*2(2x-1))

We multiply all the terms by the denominator


-153x2

We add all the numbers together, and all the variables

-153x^2

Back to the equation:

+(-153x^2)


We add all the numbers together, and all the variables

62x^2+(-153x^2)=0

We get rid of parentheses

62x^2-153x^2=0

We add all the numbers together, and all the variables

-91x^2=0

a = -91; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-91)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-182}=0$