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31/3x+20=2x
We move all terms to the left:
31/3x+20-(2x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2x+31/3x+20=0
We multiply all the terms by the denominator
-2x*3x+20*3x+31=0
Wy multiply elements
-6x^2+60x+31=0
a = -6; b = 60; c = +31;
Δ = b2-4ac
Δ = 602-4·(-6)·31
Δ = 4344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4344}=\sqrt{4*1086}=\sqrt{4}*\sqrt{1086}=2\sqrt{1086}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{1086}}{2*-6}=\frac{-60-2\sqrt{1086}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{1086}}{2*-6}=\frac{-60+2\sqrt{1086}}{-12} $
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