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31/4x+1+2x=65
We move all terms to the left:
31/4x+1+2x-(65)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
2x+31/4x-64=0
We multiply all the terms by the denominator
2x*4x-64*4x+31=0
Wy multiply elements
8x^2-256x+31=0
a = 8; b = -256; c = +31;
Δ = b2-4ac
Δ = -2562-4·8·31
Δ = 64544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{64544}=\sqrt{16*4034}=\sqrt{16}*\sqrt{4034}=4\sqrt{4034}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-256)-4\sqrt{4034}}{2*8}=\frac{256-4\sqrt{4034}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-256)+4\sqrt{4034}}{2*8}=\frac{256+4\sqrt{4034}}{16} $
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