31/5+2/5g-4/5(1-g)=2/5

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Solution for 31/5+2/5g-4/5(1-g)=2/5 equation: 



31/5+2/5g-4/5(1-g)=2/5

We move all terms to the left:

31/5+2/5g-4/5(1-g)-(2/5)=0



Domain of the equation: 5g!=0

g!=0/5

g!=0

g∈R





Domain of the equation: 5(1-g)!=0

g∈R



We add all the numbers together, and all the variables

2/5g-4/5(-1g+1)+31/5-(+2/5)=0

We get rid of parentheses

2/5g-4/5(-1g+1)+31/5-2/5=0

We calculate fractions


(10g(-)/(125g^2(-)+(-20g)/(125g^2(-)=0



We calculate terms in parentheses: +(10g(-)/(125g^2(-)+(-20g)/(125g^2(-), so:

10g(-)/(125g^2(-)+(-20g)/(125g^2(-

We can not solve this equation

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