31/5b+5=50

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Solution for 31/5b+5=50 equation: 



31/5b+5=50

We move all terms to the left:

31/5b+5-(50)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

31/5b-45=0

We multiply all the terms by the denominator


-45*5b+31=0

Wy multiply elements

-225b+31=0

We move all terms containing b to the left, all other terms to the right

-225b=-31

b=-31/-225

b=31/225

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